If cosec A = √10, find the value of [3 sin²A + 4cot²A] / [6(tan²A + cos²A)]. [Given as stacked fractions in the source; linearised here.]

Subject: Mathematics | Topic: Trigonometry | Difficulty: MEDIUM

Options

1. (A) 1089/182
2. (B) 545/91
3. (C) 726/91
4. (D) 1017/182

Verified Answer

Option (A): 1089/182

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